Post
by MKossor » Thu Sep 02, 2021 12:42 am
Steve,
The original schematic diagram you posted is fundamental correct. The horizontal line passing through switches A, C and D associated with the Hazard function should be a dashed line for better clarity showing those 3 switches are "ganged" to all switch in unison, NOT an electrical connection between those switches. Its a Triple Pole Double Throw (TPDT) switch.
The Hazard function is OFF as illustrated with all 3 switches in the left position. In other words, switches A, C and D are OPEN
The turn signal switch, F, is a Single Pole, Double Throw (SPDT) switch with Center Off function. The Ignition switch must be closed in order for the turn signal to operate. When the ignition switch is in the ON (closed) position, power is connected to the input of the blinker module. The turn signal switch can be moved from its center resting position to the left or right to activate the respective turn signal.
The Hazard function is activated by closing the hazard switch; all 3 switch elements move in unison and close together. Switch A provides power to the blinker module, switch C connects the blinker output (L) to the left signal lights and switch D connects the blinker output (L) to the right signal lights. in the hazard mode, the turn signal switch has no effect if it is switched from its normally center position to either left or right positions. There is no brake switch identified so presume that is a separate system. Hope this explanation helps with your understanding of how the blinker system works.
Regarding your simplified schematic; it appears the lower hazard switch terminal is connected to both left and right signal lights (electrically connecting them together) so when the hazard switch is open, the turn signal switch will activate all lights (ie hazard mode) if switched to either the left or right position. Thus, will ONLY function in hazard mode.
Last edited by
MKossor on Thu Sep 02, 2021 6:55 am, edited 3 times in total.